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HgCl2 is reduced to Hg2Cl2 by...

`HgCl_2 ` is reduced to `Hg_2Cl_2` by

A

`CH_4COOH`

B

`"CC"l_4`

C

HCOOH

D

`NH_3`

Text Solution

Verified by Experts

The correct Answer is:
C
`HCOOH + 2HgCl_2 rarr Hg_2Cl_2 + CO_2 + 2HCl`
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