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Match the species given in Column I with...

Match the species given in Column I with hybridisation given in Column II.
`{:(,"Column-I",,"Column-II"),("A.","Boron in"[B(OH_(4))]^(-),1.,sp^(2)),("B.","Aluminium in"[Al(H_(2)O)_(6)]^(3+),2.,sp^(3)),("C.","Boron in "B_(2)H_(6),3.,sp^(3)d^(2)),("D.","Carbon in buckminster fullerene",,),("E.","Silicon in "SiO_(4)^(4-),,),("F.","Germanium in"[GeCl_(6)]^(2-),,):}`

Text Solution

AI Generated Solution

To solve the problem of matching the species in Column I with the correct hybridization in Column II, we will analyze each species one by one, determine the number of sigma bonds, and then deduce the hybridization based on those bonds. ### Step-by-Step Solution: 1. **Species A: Boron in [B(OH)4]⁻** - Boron is bonded to four hydroxyl (OH) groups. - Count the sigma bonds: 4 (one for each OH bond). - Hybridization: Since there are 4 sigma bonds, the hybridization is **sp³**. ...
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