Which of the following figures does not represent 1 mole of dioxygen gas at STP ?

Options

A. 16 g of gas
B. 22.7 L of gas
C. `6.022xx10^(23)` dioxygen molecules
D. 11.2 L of gas

Explanation

To solve the question "Which of the following figures does not represent 1 mole of dioxygen gas at STP?", we will follow these steps:

### Step 1: Understand the definition of 1 mole of gas at STP
1 mole of any gas at Standard Temperature and Pressure (STP) occupies a volume of 22.4 liters and contains approximately 6.022 x 10^23 molecules.

### Step 2: Calculate the mass of 1 mole of dioxygen (O2)
- The molecular weight of dioxygen (O2) can be calculated as follows:
- Atomic weight of oxygen (O) = 16 g/mol
- Therefore, the molecular weight of O2 = 2 × 16 g/mol = 32 g/mol.

### Step 3: Analyze the options provided
We need to check each option against the known values for 1 mole of O2 at STP:
- **Option A:** 16 grams (Incorrect, as 1 mole of O2 is 32 grams)
- **Option B:** 22.7 liters (Incorrect, as 1 mole of O2 is 22.4 liters)
- **Option C:** 6.022 x 10^23 molecules (Correct, as this is the definition of 1 mole)
- **Option D:** 11.2 liters (Incorrect, as 1 mole of O2 is 22.4 liters)

### Step 4: Identify which options do not represent 1 mole of dioxygen gas
From our analysis:
- Options A, B, and D do not represent 1 mole of dioxygen gas at STP.
- Option C correctly represents 1 mole.

### Conclusion
The options that do not represent 1 mole of dioxygen gas at STP are A, B, and D.

### Final Answer
**Options A, B, and D do not represent 1 mole of dioxygen gas at STP.**

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