An aromatic compound 'A' (Molecular formula `C_(8)H_(8)O)`) gives positive 2, 4-DNP test. It gives a yellow precipitate of compound 'B' on treatment with iodine and sodium hydroxide solution. Compound 'A' does not give Tollen's or Fehling's test. On drastic oxidation with potassium permanganate, it forms a carboxylic acid 'C' (Molecular formula `C_(7)H_(6)O_(2)`), which is also formed along with the yellow compound in the above reaction. Identify A, B and C and write all the reactions involved.

Explanation

To solve the problem step by step, we will identify compounds A, B, and C based on the given information and reactions.

### Step 1: Determine the Structure of Compound A
- **Molecular Formula**: C8H8O
- **Degree of Unsaturation Calculation**:
\[ \text{Degree of Unsaturation} = \frac{C_n + 1 - H_n}{2} = \frac{8 + 1 - 8}{2} = \frac{1}{2} = 5 \]
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