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If cosalpha+cosbeta=0=sinalpha+sinbeta, ...

If `cosalpha+cosbeta=0=sinalpha+sinbeta`, then prove that `cos2alpha +cos2beta=-2cos(alpha +beta)`.

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To prove that \( \cos 2\alpha + \cos 2\beta = -2\cos(\alpha + \beta) \) given that \( \cos \alpha + \cos \beta = 0 \) and \( \sin \alpha + \sin \beta = 0 \), we can follow these steps: ### Step 1: Use the given equations We start with the equations: \[ \cos \alpha + \cos \beta = 0 \quad \text{(1)} \] \[ ...
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