Prove that the current flowing through an ideal inductor connected across a.c. source, lags the voltage in phase by `pi/2`.

Explanation

To prove that the current flowing through an ideal inductor connected across an AC source lags the voltage in phase by \( \frac{\pi}{2} \) radians, we can follow these steps:

### Step-by-Step Solution:

1. **Consider the AC Voltage Source**:
Let the voltage across the inductor be given by:
\[
E(t) = E_0 \sin(\omega t)
...