In the diffration due to single slit experiment, the aperture of the slit is 3 mm. If monochromatic light of wavelength 620 nm in incident normally on the slit, calculate the separation in between the first order minima and the `3^("rd")` order maxima on one side of the screen. The distance between the slit and the screen is 1.5 m.

Explanation

To solve the problem of finding the separation between the first order minima and the third order maxima in a single slit diffraction pattern, we will follow these steps:

### Step 1: Identify the given values
- Aperture of the slit, \( a = 3 \, \text{mm} = 3 \times 10^{-3} \, \text{m} \)
- Wavelength of light, \( \lambda = 620 \, \text{nm} = 620 \times 10^{-9} \, \text{m} \)
- Distance from the slit to the screen, \( D = 1.5 \, \text{m} \)

### Step 2: Calculate the position of the first order minima
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