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If a^(2) + b^(2) = 7 ab," prove that " ...

If `a^(2) + b^(2) = 7 ab," prove that " log((a+b)/3) = 1/2 (log a + log b)`.

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To prove that \( \log\left(\frac{a+b}{3}\right) = \frac{1}{2}(\log a + \log b) \) given that \( a^2 + b^2 = 7ab \), we can follow these steps: ### Step 1: Start with the given equation We have the equation: \[ a^2 + b^2 = 7ab \] ...
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