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the number of roots of the equation log(...

the number of roots of the equation `log_(3sqrtx) x + log_(3x) (sqrtx) =0` is

A

1

B

2

C

3

D

0

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To solve the equation \( \log_{3\sqrt{x}} x + \log_{3x} (\sqrt{x}) = 0 \), we will follow these steps: ### Step 1: Rewrite the logarithmic expressions Using the change of base formula, we can rewrite the logarithmic expressions: \[ \log_{3\sqrt{x}} x = \frac{\log x}{\log (3\sqrt{x})} = \frac{\log x}{\log 3 + \frac{1}{2} \log x} \] \[ \log_{3x} (\sqrt{x}) = \frac{\log (\sqrt{x})}{\log (3x)} = \frac{\frac{1}{2} \log x}{\log 3 + \log x} \] ### Step 2: Substitute back into the equation Now substituting these back into the equation, we have: \[ \frac{\log x}{\log 3 + \frac{1}{2} \log x} + \frac{\frac{1}{2} \log x}{\log 3 + \log x} = 0 \] ### Step 3: Combine the fractions To combine the fractions, we need a common denominator: \[ \frac{\log x (\log 3 + \log x) + \frac{1}{2} \log x (\log 3 + \frac{1}{2} \log x)}{(\log 3 + \frac{1}{2} \log x)(\log 3 + \log x)} = 0 \] The numerator must equal zero: \[ \log x (\log 3 + \log x) + \frac{1}{2} \log x (\log 3 + \frac{1}{2} \log x) = 0 \] ### Step 4: Factor out \(\log x\) Factoring out \(\log x\) gives: \[ \log x \left( \log 3 + \log x + \frac{1}{2} (\log 3 + \frac{1}{2} \log x) \right) = 0 \] This implies: 1. \( \log x = 0 \) which gives \( x = 1 \) 2. The other factor must also equal zero. ### Step 5: Solve the remaining equation Now we simplify the remaining equation: \[ \log 3 + \log x + \frac{1}{2} \log 3 + \frac{1}{4} \log x = 0 \] Combining like terms: \[ \left(1 + \frac{1}{4}\right) \log x + \left(1 + \frac{1}{2}\right) \log 3 = 0 \] This simplifies to: \[ \frac{5}{4} \log x + \frac{3}{2} \log 3 = 0 \] Rearranging gives: \[ \frac{5}{4} \log x = -\frac{3}{2} \log 3 \] Thus: \[ \log x = -\frac{3}{2} \cdot \frac{4}{5} \log 3 = -\frac{6}{5} \log 3 \] Exponentiating both sides: \[ x = 3^{-\frac{6}{5}} = \frac{1}{3^{\frac{6}{5}}} \] ### Step 6: Conclusion We have found two solutions: 1. \( x = 1 \) 2. \( x = 3^{-\frac{6}{5}} \) Both solutions are positive. Therefore, the total number of roots of the equation is **2**.

To solve the equation \( \log_{3\sqrt{x}} x + \log_{3x} (\sqrt{x}) = 0 \), we will follow these steps: ### Step 1: Rewrite the logarithmic expressions Using the change of base formula, we can rewrite the logarithmic expressions: \[ \log_{3\sqrt{x}} x = \frac{\log x}{\log (3\sqrt{x})} = \frac{\log x}{\log 3 + \frac{1}{2} \log x} \] \[ ...
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