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If 5, 5r and 5r^(2) are the lengths of t...

If 5, 5r and `5r^(2)` are the lengths of the sides of a triangle, then r cannot be equal to

A

`(3)/(2)`

B

`(3)/(4)`

C

`(5)/(4)`

D

`(7)/(4)`

Text Solution

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The correct Answer is:
To determine the value of \( r \) that cannot be equal to when \( 5, 5r, \) and \( 5r^2 \) are the lengths of the sides of a triangle, we will use the triangle inequality theorem. ### Step-by-Step Solution: 1. **Identify the sides of the triangle**: The sides are given as \( a = 5 \), \( b = 5r \), and \( c = 5r^2 \). 2. **Apply the triangle inequality**: The triangle inequality states that the sum of the lengths of any two sides must be greater than the length of the third side. We will set up the inequalities: - \( a + b > c \) - \( a + c > b \) - \( b + c > a \) 3. **Set up the inequalities**: - From \( 5 + 5r > 5r^2 \): \[ 5 + 5r > 5r^2 \implies 5r^2 - 5r - 5 < 0 \implies r^2 - r - 1 < 0 \] - From \( 5 + 5r^2 > 5r \): \[ 5 + 5r^2 > 5r \implies 5r^2 - 5r + 5 > 0 \] - From \( 5r + 5r^2 > 5 \): \[ 5r + 5r^2 > 5 \implies 5r^2 + 5r - 5 > 0 \] 4. **Solve the first inequality**: We focus on the first inequality \( r^2 - r - 1 < 0 \). To find the roots, we use the quadratic formula: \[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{1 \pm \sqrt{1 + 4}}{2} = \frac{1 \pm \sqrt{5}}{2} \] The roots are: \[ r_1 = \frac{1 - \sqrt{5}}{2}, \quad r_2 = \frac{1 + \sqrt{5}}{2} \] 5. **Determine the intervals**: The inequality \( r^2 - r - 1 < 0 \) holds between the roots: \[ \frac{1 - \sqrt{5}}{2} < r < \frac{1 + \sqrt{5}}{2} \] 6. **Calculate the numerical values**: - \( \frac{1 - \sqrt{5}}{2} \approx -0.618 \) - \( \frac{1 + \sqrt{5}}{2} \approx 1.618 \) 7. **Analyze the second inequality**: The second inequality \( 5r^2 - 5r + 5 > 0 \) is always true since the discriminant \( (-5)^2 - 4 \cdot 5 \cdot 5 < 0 \). 8. **Analyze the third inequality**: The third inequality \( 5r^2 + 5r - 5 > 0 \) can be solved similarly: \[ r^2 + r - 1 > 0 \] The roots are: \[ r = \frac{-1 \pm \sqrt{1 + 4}}{2} = \frac{-1 \pm \sqrt{5}}{2} \] The inequality holds outside the roots: \[ r < \frac{-1 - \sqrt{5}}{2} \quad \text{or} \quad r > \frac{-1 + \sqrt{5}}{2} \] 9. **Combine intervals**: The value of \( r \) must satisfy both conditions. The critical point to note is that \( r \) cannot equal \( \frac{7}{4} = 1.75 \), which is outside the range of the first inequality. ### Conclusion: Thus, the value of \( r \) that cannot be equal to is \( \frac{7}{4} \).
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