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The outcome of each of 30 items was obse...

The outcome of each of 30 items was observed , 10 items gave an outcome `(1)/(2)-d` each, 10 items gave outcome `(1)/(2)` each and the remaining 10 items gave outcome `(1)/(2) +d` each. If the variance of this outcome data is `(4)/(3)`, then |d| equals

A

2

B

`(sqrt(5))/(2)`

C

`(2)/(3)`

D

`sqrt(2)`

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To solve the problem, we need to find the value of |d| given the outcomes of 30 items and the variance of these outcomes. Let's break it down step by step. ### Step 1: Define the outcomes We have three groups of outcomes: - 10 items gave an outcome of \( \frac{1}{2} - d \) - 10 items gave an outcome of \( \frac{1}{2} \) - 10 items gave an outcome of \( \frac{1}{2} + d \) ### Step 2: Calculate the mean (μ) The mean (μ) of the outcomes can be calculated as follows: \[ \mu = \frac{1}{30} \left( 10 \left( \frac{1}{2} - d \right) + 10 \left( \frac{1}{2} \right) + 10 \left( \frac{1}{2} + d \right) \right) \] Calculating this gives: \[ \mu = \frac{1}{30} \left( 10 \left( \frac{1}{2} - d \right) + 10 \left( \frac{1}{2} \right) + 10 \left( \frac{1}{2} + d \right) \right) \] \[ = \frac{1}{30} \left( 5 - 10d + 5 + 5 + 10d \right) \] \[ = \frac{1}{30} \left( 15 \right) = \frac{1}{2} \] ### Step 3: Calculate the variance (σ²) The variance is given by the formula: \[ \sigma^2 = \frac{\sum (x_i^2)}{n} - \mu^2 \] Where \( n = 30 \) and \( \sigma^2 = \frac{4}{3} \). First, we calculate \( \sum (x_i^2) \): \[ \sum (x_i^2) = 10 \left( \frac{1}{2} - d \right)^2 + 10 \left( \frac{1}{2} \right)^2 + 10 \left( \frac{1}{2} + d \right)^2 \] Calculating each term: 1. \( 10 \left( \frac{1}{2} - d \right)^2 = 10 \left( \frac{1}{4} - d + d^2 \right) = \frac{10}{4} - 10d + 10d^2 \) 2. \( 10 \left( \frac{1}{2} \right)^2 = 10 \cdot \frac{1}{4} = \frac{10}{4} \) 3. \( 10 \left( \frac{1}{2} + d \right)^2 = 10 \left( \frac{1}{4} + d + d^2 \right) = \frac{10}{4} + 10d + 10d^2 \) Combining these: \[ \sum (x_i^2) = \frac{10}{4} - 10d + 10d^2 + \frac{10}{4} + \frac{10}{4} + 10d + 10d^2 \] \[ = \frac{30}{4} + 20d^2 \] ### Step 4: Substitute into the variance formula Now we substitute this back into the variance formula: \[ \frac{\frac{30}{4} + 20d^2}{30} - \left( \frac{1}{2} \right)^2 = \frac{4}{3} \] Calculating \( \left( \frac{1}{2} \right)^2 = \frac{1}{4} \): \[ \frac{30 + 80d^2}{120} - \frac{1}{4} = \frac{4}{3} \] Converting \( \frac{1}{4} \) to a fraction with a denominator of 120: \[ \frac{30 + 80d^2}{120} - \frac{30}{120} = \frac{4}{3} \] This simplifies to: \[ \frac{80d^2}{120} = \frac{4}{3} + \frac{30}{120} \] ### Step 5: Solve for d Now, we can solve for \( d^2 \): \[ \frac{80d^2}{120} = \frac{4 + 30}{120} \] \[ 80d^2 = 34 \quad \text{(after multiplying through by 120)} \] \[ d^2 = \frac{34}{80} = \frac{17}{40} \] ### Step 6: Find |d| Taking the square root of both sides: \[ |d| = \sqrt{\frac{17}{40}} = \frac{\sqrt{17}}{\sqrt{40}} = \frac{\sqrt{17}}{2\sqrt{10}} = \frac{\sqrt{17}}{2\sqrt{10}} \cdot \frac{\sqrt{10}}{\sqrt{10}} = \frac{\sqrt{170}}{20} \] Thus, the final answer is: \[ |d| = \sqrt{2} \]
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