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If the sum of the deviations of 50 obser...

If the sum of the deviations of 50 observations from 30 is 50, then the mean of these observations is

A

50

B

51

C

30

D

31

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The correct Answer is:
To solve the problem, we need to find the mean of 50 observations given that the sum of the deviations of these observations from 30 is 50. ### Step-by-Step Solution: 1. **Understanding Deviations**: The deviation of each observation from 30 can be expressed as \( x_i = \text{observation}_i - 30 \). Therefore, the sum of the deviations from 30 can be written as: \[ \sum_{i=1}^{50} (x_i) = \sum_{i=1}^{50} (\text{observation}_i - 30) = \sum_{i=1}^{50} \text{observation}_i - 30 \times 50 \] 2. **Given Information**: We are given that the sum of the deviations is 50: \[ \sum_{i=1}^{50} x_i = 50 \] 3. **Setting Up the Equation**: From the previous step, we can set up the equation: \[ \sum_{i=1}^{50} \text{observation}_i - 30 \times 50 = 50 \] Simplifying this gives: \[ \sum_{i=1}^{50} \text{observation}_i - 1500 = 50 \] 4. **Solving for the Sum of Observations**: To find the sum of the observations, we rearrange the equation: \[ \sum_{i=1}^{50} \text{observation}_i = 50 + 1500 = 1550 \] 5. **Calculating the Mean**: The mean of the observations is calculated as: \[ \text{Mean} = \frac{\sum_{i=1}^{50} \text{observation}_i}{50} = \frac{1550}{50} = 31 \] Thus, the mean of the observations is **31**.
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