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Let f(x)=lim(ntooo) (x)/(x^(2n)+1). Then...

Let `f(x)=lim_(ntooo) (x)/(x^(2n)+1).` Then f has

A

real and equal roots

B

complex roots

C

unequal positive real roots

D

unequal roots

Text Solution

Verified by Experts

The correct Answer is:
B, C, D
`f(x)=underset(xtooo)lim(x)/(x^(2n)+1)={{:(x", "x^(2)lt1),(0", "x^(2)gt1),(1//2", "x=1),(-1//2","x=-1):}`
`:.f(1^(+))=f(-1^(-))=0`
f(1^(-))=1,f(-1^(+))=-1`
`f(1)=1//2`
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