Home
Class 12
MATHS
In a triangle A B C , side A B has equat...

In a triangle `A B C ,` side `A B` has equation `2x+3y=29` and side `A C` has equation `x+2y=16.` If the midpoint of `B C` is 5, 6), then find the equation of `B Cdot`

Text Solution

AI Generated Solution

To find the equation of line segment BC in triangle ABC, we will follow these steps: ### Step 1: Identify the equations of sides AB and AC The equations of the sides are given as: - Side AB: \(2x + 3y = 29\) - Side AC: \(x + 2y = 16\) ### Step 2: Find the coordinates of point A ...
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINES

    CENGAGE ENGLISH|Exercise EXAMPLE|12 Videos
  • STRAIGHT LINES

    CENGAGE ENGLISH|Exercise CONCEPT APPLICATION EXERCISE 2.1|23 Videos
  • STRAIGHT LINE

    CENGAGE ENGLISH|Exercise Multiple Correct Answers Type|8 Videos
  • THEORY OF EQUATIONS

    CENGAGE ENGLISH|Exercise JEE ADVANCED (Numerical Value Type )|1 Videos

Similar Questions

Explore conceptually related problems

The sides A Ba n dA C of a triangle A B C are respectively 2x+3y=29a n dx+2y=16 respectively. If the mid-point of B Ci s(5,6) then find the equation of B Cdot

In triangle A B C , the equation of the right bisectors of the sides A B and A C are x+y=0 and y-x=0 , respectively. If A-=(5,7) , then find the equation of side B Cdot

The equations of the perpendicular bisectors of the sides A Ba n dA C of triangle A B C are x-y+5=0 and x+2y=0 , respectively. If the point A is (1,-2) , then find the equation of the line B Cdot

The equations of the perpendicular bisectors of the sides A Ba n dA C of triangle A B C are x-y+5=0 and x+2y=0 , respectively. If the point A is (1,-2) , then find the equation of the line B Cdot

A right-angled triangle A B C is inscribed in parabola y^2=4x , where A is the vertex of the parabola and /_B A C=pi/2dot If A B=sqrt(5), then find the area of A B Cdot

In triangle A B C , the equation of side B C is x-y=0. The circumcenter and orthocentre of triangle are (2, 3) and (5, 8), respectively. The equation of the circumcirle of the triangle is a) x^2+y^2-4x+6y-27=0 b) x^2+y^2-4x-6y-27=0 c) x^2+y^2+4x-6y-27=0 d) x^2+y^2+4x+6y-27=0

In a triangle A B C , if A is (2,-1),a n d7x-10 y+1=0 and 3x-2y+5=0 are the equations of an altitude and an angle bisector, respectively, drawn from B , then the equation of B C is (a) a+y+1=0 (b) 5x+y+17=0 (c) 4x+9y+30=0 (d) x-5y-7=0

The equations of two sides of a triangle are 3x-2y+6=0\ a n d\ 4x+5y-20\ a n d\ the orthocentre is (1,1). Find the equation of the third side.

A triangle has two sides y=m_1x and y=m_2x where m_1 and m_2 are the roots of the equation b alpha^2+2h alpha +a=0 . If (a,b) be the orthocenter of the triangle, then find the equation of the third side in terms of a , b and h .

In a triangle ABC , if the equation of sides AB,BC and CA are 2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 respectively , The equation of external bisector of angle B is