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If A^(-1)=[(1,-1,2),(0,3,1),(0,0,-1//3)]...

If `A^(-1)=[(1,-1,2),(0,3,1),(0,0,-1//3)]` , then :

A

`|A|=-1`

B

adj `A=[(-1,1,-2),(0,-3,-1),(0,0,1//3)]`

C

`A=[(1,1//3,7),(0,1//3,1),(0,0,-3)]`

D

`A=[(1,-1//3,-7),(0,-3,0),(0,0,1)]`

Text Solution

Verified by Experts

`|A^(-1)|=-1 implies |A|=-1`
Now, use adj `A=|A|A^(-1)` and `A=(A^(-1))^(-1)`
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