Home
Class 12
MATHS
The tangent to the curve y=xe^(x^2) pass...

The tangent to the curve `y=xe^(x^2)` passing through the point (1,e) also passes through the point

A

`(4/3,2e)`

B

(2, 3e)

C

`(5/3,2e)`

D

(3, 6e)

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • JEE 2019

    CENGAGE ENGLISH|Exercise Chapter 6|6 Videos
  • JEE 2019

    CENGAGE ENGLISH|Exercise Chapter 7|8 Videos
  • JEE 2019

    CENGAGE ENGLISH|Exercise Chapter 4|6 Videos
  • INVERSE TRIGONOMETRIC FUNCTIONS

    CENGAGE ENGLISH|Exercise Archives (Numerical Value type)|2 Videos
  • LIMITS

    CENGAGE ENGLISH|Exercise Comprehension Type|4 Videos

Similar Questions

Explore conceptually related problems

The tangent to the curve y=x^2-5x+5. parallel to the line 2y=4x+1, also passes through the point :

Given the curves y=f(x) passing through the point (0,1) and y=int_(-oo)^(x) f(t) passing through the point (0,(1)/(2)) The tangents drawn to both the curves at the points with equal abscissae intersect on the x-axis. Then the curve y=f(x), is

The circle passing through the point (-1,0) and touching the y-axis at (0,2) also passes through the point:

For the curve y=4x^3-2x^5, find all the points at which the tangent passes through the origin.

Curves y=f(x) passing through the point (0,1) and y=int_-oo^x f(t) dt passing through the point (0,1/n) are such that the tangents drawn to them at the point with equal abscissae intersect on x-axis. Answer the question:The equation of curve y=f(x)

Curves y=f(x) passing through the point (0,1) and y=int_-oo^x f(t) dt passing through the point (0,1/n) are such that the tangents drawn to them at the point with equal abscissae intersect on x axis. find Curve y=f(x)

Curves y=f(x) passing through the point (0,1) and y=int_-oo^x f(t) dt passing through the point (0,1/n) are such that the tangents drawn to them at the point with equal abscissae intersect on x axis

For the curve y=4x^3-2x^5, find all the points at which the tangents pass through the origin.

If the line y=2x touches the curve y=ax^(2)+bx+c at the point where x=1 and the curve passes through the point (-1,0), then

For the curve y=4x^3-2x^5 find all points at which the tangent passes through the origin.