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If (a costheta1,asintheta1),(acostheta2,...

If `(a costheta_1,asintheta_1),(acostheta_2,a sintheta_2)`, and `(acostheta_3a sintheta_3)` represent the vertces of an equilateral triangle inscribed in a circle. Then.

A

`costheta_1+costheta_2+costheta_3=0`

B

`sintheta_1+sintheta_2+sin theta_3=0`

C

`tantheta_1+tantheta_2+tantheta_3=0`

D

`cottheta_1+cottheta_2+cottheta_3=0`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to show that the sum of the x-coordinates and the sum of the y-coordinates of the vertices of the equilateral triangle are both equal to zero. ### Step-by-Step Solution: 1. **Identify the Vertices**: The vertices of the equilateral triangle are given as: - \( A = (a \cos \theta_1, a \sin \theta_1) \) - \( B = (a \cos \theta_2, a \sin \theta_2) \) - \( C = (a \cos \theta_3, a \sin \theta_3) \) 2. **Find the Centroid**: The centroid \( G \) of the triangle formed by these vertices is given by the formula: \[ G = \left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right) \] Substituting the coordinates of the vertices: \[ G = \left( \frac{a \cos \theta_1 + a \cos \theta_2 + a \cos \theta_3}{3}, \frac{a \sin \theta_1 + a \sin \theta_2 + a \sin \theta_3}{3} \right) \] 3. **Set the Centroid to the Origin**: Since the triangle is inscribed in a circle and is equilateral, the centroid coincides with the circumcenter, which is at the origin (0, 0). Therefore, we set: \[ \frac{a \cos \theta_1 + a \cos \theta_2 + a \cos \theta_3}{3} = 0 \] \[ \frac{a \sin \theta_1 + a \sin \theta_2 + a \sin \theta_3}{3} = 0 \] 4. **Simplify the Equations**: Multiplying both equations by 3 gives: \[ a \cos \theta_1 + a \cos \theta_2 + a \cos \theta_3 = 0 \] \[ a \sin \theta_1 + a \sin \theta_2 + a \sin \theta_3 = 0 \] 5. **Conclude the Results**: Since \( a \) is a non-zero constant (the radius of the circle), we can divide both equations by \( a \): \[ \cos \theta_1 + \cos \theta_2 + \cos \theta_3 = 0 \] \[ \sin \theta_1 + \sin \theta_2 + \sin \theta_3 = 0 \] ### Final Result: Thus, we conclude that: - The sum of the cosines of the angles is zero. - The sum of the sines of the angles is zero.

To solve the problem, we need to show that the sum of the x-coordinates and the sum of the y-coordinates of the vertices of the equilateral triangle are both equal to zero. ### Step-by-Step Solution: 1. **Identify the Vertices**: The vertices of the equilateral triangle are given as: - \( A = (a \cos \theta_1, a \sin \theta_1) \) - \( B = (a \cos \theta_2, a \sin \theta_2) \) ...
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