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P (vecp) and Q (vecq) are the position v...

P `(vecp) and Q (vecq)` are the position vectors of two fixed points and `R(vecr)` is the postion vector of a variable point. If R moves such that `(vecr-vecp)xx (vecr-vecq)=vec0`then the locus of R is

A

a plane containing the origian O and parallel to two non-collinear vectors `vec(OP) and vec(OQ) `

B

the surface of a sphere described on PQ as its diameter

C

a line passing through points P and Q

D

a set of lines parallel to line PQ

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The correct Answer is:
To solve the problem, we need to analyze the given condition involving the position vectors of points P, Q, and R. Let's go through the steps systematically. ### Step-by-Step Solution 1. **Understand the Given Condition**: We are given that the position vectors of points P and Q are denoted by \(\vec{p}\) and \(\vec{q}\), respectively. The position vector of the variable point R is denoted by \(\vec{r}\). The condition given is: \[ (\vec{r} - \vec{p}) \times (\vec{r} - \vec{q}) = \vec{0} \] 2. **Interpret the Cross Product**: The cross product of two vectors is zero if and only if the vectors are collinear. Therefore, the condition implies that the vectors \(\vec{r} - \vec{p}\) and \(\vec{r} - \vec{q}\) are collinear. 3. **Express Collinearity**: If the vectors are collinear, we can express this relationship as: \[ \vec{r} - \vec{p} = k(\vec{r} - \vec{q}) \] for some scalar \(k\). 4. **Rearranging the Equation**: Rearranging the equation gives: \[ \vec{r} - \vec{p} = k\vec{r} - k\vec{q} \] This can be rearranged to isolate \(\vec{r}\): \[ \vec{r} - k\vec{r} = k\vec{q} + \vec{p} \] \[ \vec{r}(1 - k) = k\vec{q} + \vec{p} \] Hence, \[ \vec{r} = \frac{k\vec{q} + \vec{p}}{1 - k} \] 5. **Interpret the Result**: The expression shows that \(\vec{r}\) can be expressed as a linear combination of \(\vec{p}\) and \(\vec{q}\). This means that point R lies on the line that passes through points P and Q. 6. **Conclusion**: Therefore, the locus of the point R is a straight line passing through the fixed points P and Q. ### Final Answer: The locus of R is a straight line passing through points P and Q.

To solve the problem, we need to analyze the given condition involving the position vectors of points P, Q, and R. Let's go through the steps systematically. ### Step-by-Step Solution 1. **Understand the Given Condition**: We are given that the position vectors of points P and Q are denoted by \(\vec{p}\) and \(\vec{q}\), respectively. The position vector of the variable point R is denoted by \(\vec{r}\). The condition given is: \[ (\vec{r} - \vec{p}) \times (\vec{r} - \vec{q}) = \vec{0} ...
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CENGAGE ENGLISH-DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS -Exercises MCQ
  1. If hata,hatb and hatc are three unit vectors such that hata + hatb + h...

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  2. If veca, vecb, vecc are unit vectors such that veca. vecb =0 = veca.ve...

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  3. P (vecp) and Q (vecq) are the position vectors of two fixed points and...

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  4. Two adjacent sides of a parallelogram ABCD are 2hati+4hatj -5 hatkand ...

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  5. If hat a , hat b ,a n d hat c are three unit vectors inclined to ea...

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  6. Let the pair of vector veca,vecb and vecc,veccd each determine a plane...

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  7. If vecr.veca=vecr.vecb=vecr.vecc=0 " where "veca,vecb and vecc are non...

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  8. If veca satisfies vecaxx(hati+2hatj+hatk)=hati-hatk" then " veca is eq...

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  9. Vectors 3veca-5vecb and 2veca + vecb are mutually perpendicular. If ve...

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  10. The units vectors orthogonal to the vector - hat i + 2hat j + 2hat k ...

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  11. The value of x for which the angle between veca = 2x^(2) hati + 4x h...

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  12. If vectors veca and vecb are two adjacent sides of parallelograsm then...

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  13. A parallelogram is constructed on 3veca+vecb and veca-4vecb, where |ve...

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  14. Let veca.vecb=0 where veca and vecb are unit vectors and the vector ve...

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  15. veca and vecc are unit vectors and |vecb|=4 the angle between veca and...

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  16. Let the position vectors of the points Pa n dQ be 4 hat i+ hat j+lam...

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  17. A vector of magnitude sqrt2 coplanar with the vectors veca=hati+hatj+2...

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  18. Let P be a point interior to the acute triangle A B Cdot If P A+P B...

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  19. G is the centroid of triangle ABC and A1 and B1 are the midpoints of s...

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  20. Points veca , vecb vecc and vecd are coplanar and (sin alpha)veca + (2...

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