If vecr=x(1)(vecaxx vecb) + x(2) (vecb x...

If `vecr=x_(1)(vecaxx vecb) + x_(2) (vecb xxveca) + x_(3)(vecc xxvecd) and 4[veca vecb vecc] =1 " then " x_(1) + x_(2) + x_(3)` is equal to

`1/2vecr.(veca + vecb + vecc)`

`1/4vecr.(veca + vecb + vecc)`

`2vecr.(veca + vecb + vecc)`

`4vecr.(veca + vecb + vecc)`

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The correct Answer is:

`vecr= x_(1)(vecaxx vecb) + x_(2)(vecb xx vecc)+x_(3)(vecc xxveca)`
`Rightarrow vecr.veca=x_(2)[veca vecb vecc] . vecr.vecb=x_(3)[vecb vecc veca]`
` and vecr.vecc= x_(1)[vecc veca vecb] =x_(1) [vecb vecc veca]`
` Rightarrow x_(1)+x_(2)+x_(3)=4vecr. (veca +vecb+vecc)`

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