To evaluate the integral \( \int \sin 2x \sin 3x \, dx \), we can follow these steps:
### Step 1: Multiply and divide by 2
We start by multiplying and dividing the integral by 2:
\[
\int \sin 2x \sin 3x \, dx = \frac{1}{2} \int 2 \sin 2x \sin 3x \, dx
\]
...