Evaluate: `inte^x\ (logx+1/(x^2))\ dx`

Explanation

To evaluate the integral \( I = \int e^x \left( \log x + \frac{1}{x^2} \right) dx \), we can break it down into two separate integrals:

\[ I = \int e^x \log x \, dx + \int e^x \frac{1}{x^2} \, dx \]

### Step 1: Evaluate \( \int e^x \log x \, dx \)

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