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In triangle ABC, if r(1) = 2r(2) = 3r(3)...

In triangle ABC, if `r_(1) = 2r_(2) = 3r_(3)`, then `a : b` is equal to

A

`(5)/(4)`

B

`(4)/(5)`

C

`(7)/(4)`

D

`(4)/(7)`

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The correct Answer is:
To solve the problem, we need to find the ratio \( a : b \) in triangle \( ABC \) given that \( r_1 = 2r_2 = 3r_3 \). Here’s a step-by-step solution: ### Step 1: Set up the equations based on the given information We know that: - \( r_1 = \frac{\Delta}{s-a} \) - \( r_2 = \frac{\Delta}{s-b} \) - \( r_3 = \frac{\Delta}{s-c} \) From the problem, we have: \[ r_1 = 2r_2 = 3r_3 \] ### Step 2: Express the ratios in terms of \( k \) Let’s denote: \[ r_1 = k, \quad r_2 = \frac{k}{2}, \quad r_3 = \frac{k}{3} \] This gives us the following equations: \[ \frac{1}{s-a} = \frac{1}{k} \] \[ \frac{1}{s-b} = \frac{2}{k} \] \[ \frac{1}{s-c} = \frac{3}{k} \] ### Step 3: Rearranging the equations From these equations, we can express \( s-a \), \( s-b \), and \( s-c \): 1. \( s-a = \frac{k}{1} \) 2. \( s-b = \frac{k}{2} \) 3. \( s-c = \frac{k}{3} \) ### Step 4: Solve for \( s \) Now, we can add these three equations: \[ (s-a) + (s-b) + (s-c) = k + \frac{k}{2} + \frac{k}{3} \] To combine the right side, find a common denominator (which is 6): \[ k + \frac{3k}{6} + \frac{2k}{6} = k + \frac{5k}{6} = \frac{11k}{6} \] Thus, we have: \[ 3s - (a + b + c) = \frac{11k}{6} \] ### Step 5: Relate \( a + b + c \) to \( s \) Since \( a + b + c = 2s \) (by the definition of semi-perimeter \( s \)): \[ 3s - 2s = \frac{11k}{6} \] This simplifies to: \[ s = \frac{11k}{6} \] ### Step 6: Substitute \( s \) back to find \( a \) and \( b \) Now substituting \( s \) back into the equations for \( a \) and \( b \): 1. For \( a \): \[ a = s - (s-a) = \frac{11k}{6} - k = \frac{11k}{6} - \frac{6k}{6} = \frac{5k}{6} \] 2. For \( b \): \[ b = s - (s-b) = \frac{11k}{6} - \frac{k}{2} = \frac{11k}{6} - \frac{3k}{6} = \frac{8k}{6} = \frac{4k}{3} \] ### Step 7: Find the ratio \( a : b \) Now we can find the ratio \( a : b \): \[ a : b = \frac{5k/6}{4k/3} = \frac{5}{6} \cdot \frac{3}{4} = \frac{15}{24} = \frac{5}{8} \] Thus, the final answer is: \[ a : b = 5 : 4 \]

To solve the problem, we need to find the ratio \( a : b \) in triangle \( ABC \) given that \( r_1 = 2r_2 = 3r_3 \). Here’s a step-by-step solution: ### Step 1: Set up the equations based on the given information We know that: - \( r_1 = \frac{\Delta}{s-a} \) - \( r_2 = \frac{\Delta}{s-b} \) - \( r_3 = \frac{\Delta}{s-c} \) ...
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