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Let a,b,c,d be real numbers such that |a...

Let a,b,c,d be real numbers such that |a-b|=2, |b-c|=3, |c-d|=4 Then the sum of all possible values of |a-d|=

A

`9`

B

`18`

C

`24`

D

`30`

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The correct Answer is:
To solve the problem step by step, we will analyze the given absolute value equations and derive the possible values of \(|a-d|\). ### Step 1: Set up the equations based on absolute values We have the following equations based on the problem statement: 1. \(|a - b| = 2\) 2. \(|b - c| = 3\) 3. \(|c - d| = 4\) From these equations, we can express them as: - \(a - b = 2\) or \(a - b = -2\) - \(b - c = 3\) or \(b - c = -3\) - \(c - d = 4\) or \(c - d = -4\) ### Step 2: Explore all combinations of signs We will explore all combinations of the signs for the equations. This will give us different values for \(a - d\). #### Case 1: All positive signs - \(a - b = 2\) - \(b - c = 3\) - \(c - d = 4\) Adding these gives: \[ a - d = (a - b) + (b - c) + (c - d) = 2 + 3 + 4 = 9 \] #### Case 2: All negative signs - \(a - b = -2\) - \(b - c = -3\) - \(c - d = -4\) Adding these gives: \[ a - d = (-2) + (-3) + (-4) = -9 \] #### Case 3: Two positive, one negative - \(a - b = 2\) - \(b - c = 3\) - \(c - d = -4\) Adding these gives: \[ a - d = 2 + 3 - 4 = 1 \] #### Case 4: One positive, two negative - \(a - b = -2\) - \(b - c = -3\) - \(c - d = 4\) Adding these gives: \[ a - d = -2 - 3 + 4 = -1 \] #### Case 5: One positive, one negative, one positive - \(a - b = 2\) - \(b - c = -3\) - \(c - d = 4\) Adding these gives: \[ a - d = 2 - 3 + 4 = 3 \] #### Case 6: One negative, one positive, one negative - \(a - b = -2\) - \(b - c = 3\) - \(c - d = -4\) Adding these gives: \[ a - d = -2 + 3 - 4 = -3 \] #### Case 7: Two negatives, one positive - \(a - b = -2\) - \(b - c = -3\) - \(c - d = 4\) Adding these gives: \[ a - d = -2 - 3 + 4 = -1 \] #### Case 8: Two positives, one negative - \(a - b = 2\) - \(b - c = 3\) - \(c - d = -4\) Adding these gives: \[ a - d = 2 + 3 - 4 = 1 \] ### Step 3: Collect all possible values of \(|a - d|\) From the cases, we have the following possible values for \(a - d\): - \(9\) - \(-9\) - \(1\) - \(-1\) - \(3\) - \(-3\) Taking the absolute values, we have: - \(|9| = 9\) - \(|-9| = 9\) - \(|1| = 1\) - \(|-1| = 1\) - \(|3| = 3\) - \(|-3| = 3\) Thus, the unique absolute values are: - \(1, 3, 9\) ### Step 4: Sum all unique possible values of \(|a - d|\) Now we sum the unique values: \[ 1 + 3 + 9 = 13 \] ### Final Answer The sum of all possible values of \(|a - d|\) is \(13\).

To solve the problem step by step, we will analyze the given absolute value equations and derive the possible values of \(|a-d|\). ### Step 1: Set up the equations based on absolute values We have the following equations based on the problem statement: 1. \(|a - b| = 2\) 2. \(|b - c| = 3\) 3. \(|c - d| = 4\) ...
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