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If f(a-x)=f(a+x) " and " f(b-x)=f(b+x) f...

If `f(a-x)=f(a+x) " and " f(b-x)=f(b+x)` for all real x, where `a, b (a gt b gt 0)` are constants, then prove that `f(x)` is a periodic function.

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To prove that the function \( f(x) \) is periodic given the conditions \( f(a-x) = f(a+x) \) and \( f(b-x) = f(b+x) \) for all real \( x \), we can follow these steps: ### Step 1: Analyze the given equations We have two equations: 1. \( f(a - x) = f(a + x) \) (Equation 1) 2. \( f(b - x) = f(b + x) \) (Equation 2) ### Step 2: Substitute \( x \) in terms of \( b \) ...
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