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The domain of f9x)=((log)2(x+3))/(x^2+3x...

The domain of `f9x)=((log)_2(x+3))/(x^2+3x+2)` is `R-{-1,2}` (b) `(-2,oo)` `R-{-1,-2,-3}` (d) `(-3,oo)-(-1,-2}`

A

`R-{-1,-2}`

B

`(-2,oo)`

C

`R-{-1,-2,-3}`

D

`(-3,oo)-{-1,-2}`

Text Solution

Verified by Experts

The correct Answer is:
D
Here, `x+3 gt 0 " and " x^(2)+3x+2 ne 0.`
Therefore, `x gt -3 " and " (x+1)(x+2) ne 0, "i.e.," x ne -1,-2.`
Therefore, the domain is `(-3,oo)-{-1,-2}.`
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