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The range of the function f(x)=|x-1|+|x-...

The range of the function `f(x)=|x-1|+|x-2|, -1 le x le 3,` is

A

[1, 3]

B

[1, 5]

C

[3, 5]

D

None of these

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To find the range of the function \( f(x) = |x - 1| + |x - 2| \) for the interval \( -1 \leq x \leq 3 \), we will analyze the function by breaking it down based on the critical points where the expression inside the absolute values changes sign. The critical points here are \( x = 1 \) and \( x = 2 \). ### Step 1: Identify the intervals The critical points divide the interval \( [-1, 3] \) into three segments: 1. \( x \in [-1, 1] \) 2. \( x \in [1, 2] \) 3. \( x \in [2, 3] \) ### Step 2: Evaluate \( f(x) \) in each interval **Interval 1: \( x \in [-1, 1] \)** - In this interval, both \( x - 1 \) and \( x - 2 \) are negative. - Therefore, we have: \[ f(x) = -(x - 1) - (x - 2) = -x + 1 - x + 2 = -2x + 3 \] - Evaluating at the endpoints: - At \( x = -1 \): \[ f(-1) = -2(-1) + 3 = 2 + 3 = 5 \] - At \( x = 1 \): \[ f(1) = -2(1) + 3 = -2 + 3 = 1 \] **Interval 2: \( x \in [1, 2] \)** - In this interval, \( x - 1 \) is non-negative and \( x - 2 \) is negative. - Therefore, we have: \[ f(x) = (x - 1) - (x - 2) = x - 1 - x + 2 = 1 \] - Here, \( f(x) \) is constant and equal to 1 for all \( x \) in this interval. **Interval 3: \( x \in [2, 3] \)** - In this interval, both \( x - 1 \) and \( x - 2 \) are non-negative. - Therefore, we have: \[ f(x) = (x - 1) + (x - 2) = x - 1 + x - 2 = 2x - 3 \] - Evaluating at the endpoints: - At \( x = 2 \): \[ f(2) = 2(2) - 3 = 4 - 3 = 1 \] - At \( x = 3 \): \[ f(3) = 2(3) - 3 = 6 - 3 = 3 \] ### Step 3: Compile the results From our evaluations: - In the interval \( [-1, 1] \), \( f(x) \) varies from \( 5 \) to \( 1 \). - In the interval \( [1, 2] \), \( f(x) = 1 \). - In the interval \( [2, 3] \), \( f(x) \) varies from \( 1 \) to \( 3 \). ### Step 4: Determine the range Combining all the values, we see that: - The minimum value of \( f(x) \) is \( 1 \) (which occurs in both the intervals \( [1, 2] \) and \( [2, 3] \)). - The maximum value of \( f(x) \) is \( 5 \) (which occurs at \( x = -1 \)). Thus, the range of the function \( f(x) \) is: \[ \text{Range} = [1, 5] \]

To find the range of the function \( f(x) = |x - 1| + |x - 2| \) for the interval \( -1 \leq x \leq 3 \), we will analyze the function by breaking it down based on the critical points where the expression inside the absolute values changes sign. The critical points here are \( x = 1 \) and \( x = 2 \). ### Step 1: Identify the intervals The critical points divide the interval \( [-1, 3] \) into three segments: 1. \( x \in [-1, 1] \) 2. \( x \in [1, 2] \) 3. \( x \in [2, 3] \) ...
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