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The function f:R to R is defined by f(x)...

The function `f:R to R` is defined by `f(x)=cos^(2)x+sin^(4)x` for `x in R`. Then the range of `f(x)` is

A

`((3)/(4),1]`

B

`[(3)/(4),1)`

C

`[(3)/(4),1]`

D

`((3)/(4),1)`

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The correct Answer is:
To find the range of the function \( f(x) = \cos^2 x + \sin^4 x \), we can follow these steps: ### Step 1: Rewrite the function We start with the function: \[ f(x) = \cos^2 x + \sin^4 x \] We can express \(\sin^4 x\) in terms of \(\cos^2 x\): \[ \sin^4 x = (\sin^2 x)^2 = (1 - \cos^2 x)^2 \] So, we rewrite \(f(x)\) as: \[ f(x) = \cos^2 x + (1 - \cos^2 x)^2 \] ### Step 2: Expand the expression Now, we expand \((1 - \cos^2 x)^2\): \[ (1 - \cos^2 x)^2 = 1 - 2\cos^2 x + \cos^4 x \] Substituting this back into our function gives: \[ f(x) = \cos^2 x + 1 - 2\cos^2 x + \cos^4 x \] This simplifies to: \[ f(x) = 1 - \cos^2 x + \cos^4 x \] ### Step 3: Substitute \(y = \cos^2 x\) Let \(y = \cos^2 x\). Since \(\cos^2 x\) can take values in the range \([0, 1]\), we substitute \(y\) into the function: \[ f(y) = 1 - y + y^2 \] ### Step 4: Analyze the function \(f(y)\) We need to find the range of the quadratic function: \[ f(y) = y^2 - y + 1 \] This is a parabola that opens upwards (since the coefficient of \(y^2\) is positive). ### Step 5: Find the vertex The vertex of a quadratic function \(ax^2 + bx + c\) occurs at \(y = -\frac{b}{2a}\). Here, \(a = 1\) and \(b = -1\): \[ y = -\frac{-1}{2 \cdot 1} = \frac{1}{2} \] Now we evaluate \(f\) at \(y = \frac{1}{2}\): \[ f\left(\frac{1}{2}\right) = \left(\frac{1}{2}\right)^2 - \left(\frac{1}{2}\right) + 1 = \frac{1}{4} - \frac{1}{2} + 1 = \frac{1}{4} - \frac{2}{4} + \frac{4}{4} = \frac{3}{4} \] ### Step 6: Evaluate endpoints Now we evaluate \(f(y)\) at the endpoints \(y = 0\) and \(y = 1\): - For \(y = 0\): \[ f(0) = 0^2 - 0 + 1 = 1 \] - For \(y = 1\): \[ f(1) = 1^2 - 1 + 1 = 1 \] ### Step 7: Determine the range The minimum value of \(f(y)\) occurs at the vertex \(y = \frac{1}{2}\) and is \(\frac{3}{4}\). The maximum value occurs at the endpoints \(y = 0\) and \(y = 1\) and is \(1\). Thus, the range of \(f(x)\) is: \[ \boxed{\left[\frac{3}{4}, 1\right]} \]

To find the range of the function \( f(x) = \cos^2 x + \sin^4 x \), we can follow these steps: ### Step 1: Rewrite the function We start with the function: \[ f(x) = \cos^2 x + \sin^4 x \] We can express \(\sin^4 x\) in terms of \(\cos^2 x\): ...
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