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If the graph of the function `f(x)=(a^x-1)/(x^n(a^x+1))` is symmetrical about the `y-a xi s ,t h e nn` equals 2 (b) `2/3` (c) `1/4` (d) `1/3`

A

2

B

`(2)/(3)`

C

`(4)/(3)`

D

`-(1)/(3)`

Text Solution

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The correct Answer is:
To determine the value of \( n \) for which the function \[ f(x) = \frac{a^x - 1}{x^n (a^x + 1)} \] is symmetric about the y-axis, we need to establish the condition for symmetry. A function is symmetric about the y-axis if \[ f(x) = f(-x). \] ### Step 1: Find \( f(-x) \) First, we calculate \( f(-x) \): \[ f(-x) = \frac{a^{-x} - 1}{(-x)^n (a^{-x} + 1)}. \] ### Step 2: Simplify \( f(-x) \) We can rewrite \( a^{-x} \) as \( \frac{1}{a^x} \): \[ f(-x) = \frac{\frac{1}{a^x} - 1}{(-x)^n \left(\frac{1}{a^x} + 1\right)}. \] Now, simplifying the numerator and denominator: \[ = \frac{\frac{1 - a^x}{a^x}}{(-x)^n \left(\frac{1 + a^x}{a^x}\right)} = \frac{1 - a^x}{(-x)^n (1 + a^x)}. \] ### Step 3: Set \( f(-x) = f(x) \) Now we set \( f(-x) \) equal to \( f(x) \): \[ \frac{1 - a^x}{(-x)^n (1 + a^x)} = \frac{a^x - 1}{x^n (a^x + 1)}. \] ### Step 4: Cross-multiply Cross-multiplying gives us: \[ (1 - a^x) x^n (a^x + 1) = (a^x - 1)(-x)^n (1 + a^x). \] ### Step 5: Expand both sides Expanding both sides: Left side: \[ x^n (1 - a^x)(a^x + 1) = x^n (a^x + 1 - a^{2x} - a^x) = x^n (1 - a^{2x}). \] Right side: \[ -(a^x - 1)(-x)^n (1 + a^x) = (a^x - 1)x^n (1 + a^x) = (a^{2x} - a^x - x^n + 1). \] ### Step 6: Equate coefficients Now we equate the coefficients from both sides. This leads to the conclusion that for the equation to hold true, the powers of \( x \) must match, which implies that \( n \) must be odd. ### Step 7: Analyze the options The options given are: - (a) \( 2 \) - (b) \( \frac{2}{3} \) - (c) \( \frac{1}{4} \) - (d) \( \frac{1}{3} \) Since \( n \) must be an odd integer, we can check which of these options is odd: - \( 2 \) is even. - \( \frac{2}{3} \) is not an integer. - \( \frac{1}{4} \) is not an integer. - \( \frac{1}{3} \) is not an integer. The only option that satisfies the condition of being an odd integer is \( \frac{1}{3} \). ### Final Answer Thus, the value of \( n \) that makes the function symmetric about the y-axis is \[ \boxed{\frac{1}{3}}. \]

To determine the value of \( n \) for which the function \[ f(x) = \frac{a^x - 1}{x^n (a^x + 1)} \] is symmetric about the y-axis, we need to establish the condition for symmetry. A function is symmetric about the y-axis if ...
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