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If f is periodic, g is polynomial functi...

If `f` is periodic, `g` is polynomial function and `f(g(x))` is periodic and `g(2)=3,g(4)= 7` then `g(6)` is

A

13

B

15

C

11

D

None of these

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The correct Answer is:
To solve the problem, we need to find the value of \( g(6) \) given that \( g \) is a polynomial function and we have the values of \( g(2) = 3 \) and \( g(4) = 7 \). ### Step 1: Assume the form of the polynomial Since we have only two values, we can assume that \( g(x) \) is a linear polynomial of the form: \[ g(x) = ax + b \] ### Step 2: Set up equations using the given values Using the given values: 1. For \( g(2) = 3 \): \[ 2a + b = 3 \quad \text{(Equation 1)} \] 2. For \( g(4) = 7 \): \[ 4a + b = 7 \quad \text{(Equation 2)} \] ### Step 3: Subtract the equations to eliminate \( b \) Now, we can subtract Equation 1 from Equation 2 to find \( a \): \[ (4a + b) - (2a + b) = 7 - 3 \] This simplifies to: \[ 2a = 4 \] Thus, we find: \[ a = 2 \] ### Step 4: Substitute \( a \) back to find \( b \) Now, substitute \( a = 2 \) back into Equation 1 to find \( b \): \[ 2(2) + b = 3 \] This simplifies to: \[ 4 + b = 3 \] So, we find: \[ b = 3 - 4 = -1 \] ### Step 5: Write the polynomial function Now we can write the polynomial function: \[ g(x) = 2x - 1 \] ### Step 6: Calculate \( g(6) \) Finally, we can find \( g(6) \): \[ g(6) = 2(6) - 1 = 12 - 1 = 11 \] ### Final Answer Thus, the value of \( g(6) \) is: \[ \boxed{11} \]

To solve the problem, we need to find the value of \( g(6) \) given that \( g \) is a polynomial function and we have the values of \( g(2) = 3 \) and \( g(4) = 7 \). ### Step 1: Assume the form of the polynomial Since we have only two values, we can assume that \( g(x) \) is a linear polynomial of the form: \[ g(x) = ax + b \] ...
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