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If the line x+2b y+7=0 is a diameter of ...

If the line `x+2b y+7=0` is a diameter of the circle `x^2+y^2-6x+2y=0` , then find the value of `b`.

Text Solution

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The correct Answer is:
`b=5`
Here the center of the circle, (3,-1) , must lie on the line `x+2by+7=0`. Therefore,
`3-2b+7=0` or `b=5`
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