For all `theta` in `[0,pi/2]` show that the `"cos"(sintheta)geq"sin"(costheta)`

Explanation

To prove that \( \cos(\sin \theta) \geq \sin(\cos \theta) \) for all \( \theta \) in the interval \( [0, \frac{\pi}{2}] \), we can follow these steps:

### Step 1: Analyze the functions involved
We start by considering the functions \( \cos(\sin \theta) \) and \( \sin(\cos \theta) \). Since \( \theta \) is in the interval \( [0, \frac{\pi}{2}] \), both \( \sin \theta \) and \( \cos \theta \) will take values in the range \( [0, 1] \).

### Step 2: Use the identity for cosine and sine
We can express \( \cos(\sin \theta) \) and \( \sin(\cos \theta) \) in terms of their Taylor series or use the properties of these functions. However, we will use a different approach involving the sum of angles.

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