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If `A, B and C` are three values lying in `[0, 2pi]` for which `tan theta = K` then `tan""(A)/(3) tan ""(B)/(3) + tan ""(B)/(3)tan ""(C )/(3) + tan ""(C )/(3)tan ""(A)/(3)` is equal to ___________.

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To solve the problem, we need to evaluate the expression: \[ \frac{\tan A}{3} \cdot \frac{\tan B}{3} + \frac{\tan B}{3} \cdot \frac{\tan C}{3} + \frac{\tan C}{3} \cdot \frac{\tan A}{3} \] Let's denote \( x = \frac{\tan A}{3} \), \( y = \frac{\tan B}{3} \), and \( z = \frac{\tan C}{3} \). Thus, we can rewrite the expression as: \[ xy + yz + zx \] ### Step 1: Relate \( \tan A, \tan B, \tan C \) to \( K \) Given that \( \tan \theta = K \), we can express \( \tan A, \tan B, \tan C \) in terms of \( K \). We know that: \[ \tan A = 3x, \quad \tan B = 3y, \quad \tan C = 3z \] ### Step 2: Use the identity for \( \tan 3\theta \) Using the identity for \( \tan 3\theta \): \[ \tan 3\theta = \frac{3\tan \theta - \tan^3 \theta}{1 - 3\tan^2 \theta} \] Substituting \( \tan \theta = K \): \[ \tan 3\theta = \frac{3K - K^3}{1 - 3K^2} \] ### Step 3: Set up the cubic equation Assuming \( \tan A, \tan B, \tan C \) are the roots of the cubic equation derived from the identity, we can express it as: \[ t^3 - 3K t^2 + 3K t - K = 0 \] ### Step 4: Identify the coefficients From the cubic equation \( t^3 + pt^2 + qt + r = 0 \), we can identify: - The sum of the roots \( (A + B + C) = 3K \) - The sum of the product of the roots taken two at a time \( (AB + BC + CA) = 3K \) - The product of the roots \( (ABC) = K \) ### Step 5: Calculate \( xy + yz + zx \) From the above, we know: \[ xy + yz + zx = \frac{1}{9}(AB + BC + CA) = \frac{1}{9}(3K) = \frac{K}{3} \] ### Final Result Thus, the expression simplifies to: \[ \frac{K}{3} \] ### Summary of Steps 1. Define \( x, y, z \) in terms of \( \tan A, \tan B, \tan C \). 2. Use the identity for \( \tan 3\theta \) to relate it to \( K \). 3. Set up the cubic equation with roots \( \tan A, \tan B, \tan C \). 4. Identify the coefficients of the cubic equation. 5. Calculate \( xy + yz + zx \) using the identified coefficients.

To solve the problem, we need to evaluate the expression: \[ \frac{\tan A}{3} \cdot \frac{\tan B}{3} + \frac{\tan B}{3} \cdot \frac{\tan C}{3} + \frac{\tan C}{3} \cdot \frac{\tan A}{3} \] Let's denote \( x = \frac{\tan A}{3} \), \( y = \frac{\tan B}{3} \), and \( z = \frac{\tan C}{3} \). Thus, we can rewrite the expression as: ...
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