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Find the number of real solution of the equation `(cos x)^(5)+(sin x)^(3)=1` in the interval `[0, 2pi]`

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To find the number of real solutions for the equation \((\cos x)^5 + (\sin x)^3 = 1\) in the interval \([0, 2\pi]\), we can follow these steps: ### Step 1: Analyze the equation The equation is given as: \[ (\cos x)^5 + (\sin x)^3 = 1 \] We know that both \((\cos x)^5\) and \((\sin x)^3\) are non-negative for values of \(x\) in the interval \([0, 2\pi]\). ### Step 2: Identify the maximum values The maximum value of \((\cos x)^5\) occurs when \(\cos x = 1\), which gives \((\cos x)^5 = 1\). The maximum value of \((\sin x)^3\) occurs when \(\sin x = 1\), which gives \((\sin x)^3 = 1\). Therefore, the maximum sum of \((\cos x)^5 + (\sin x)^3\) can be at most 1. ### Step 3: Set conditions for the equation to hold For the equation \((\cos x)^5 + (\sin x)^3 = 1\) to hold, we can consider two cases: 1. \((\cos x)^5 = 1\) and \((\sin x)^3 = 0\) 2. \((\cos x)^5 < 1\) and \((\sin x)^3 > 0\) ### Step 4: Solve for the first case For the first case: - \((\cos x)^5 = 1\) implies \(\cos x = 1\). This occurs at: - \(x = 0\) - \(x = 2\pi\) - \((\sin x)^3 = 0\) implies \(\sin x = 0\). This occurs at: - \(x = 0\) - \(x = \pi\) - \(x = 2\pi\) From this case, we have the solutions \(x = 0\) and \(x = 2\pi\). ### Step 5: Solve for the second case For the second case: - We need to find values of \(x\) where \((\cos x)^5 + (\sin x)^3 = 1\) holds true but neither term is equal to 1 exclusively. This can occur when: - \(\cos x\) is less than 1 (which means \(\sin x\) must be greater than 0, thus \(0 < x < \pi\)). - We need to check specific angles within this range. ### Step 6: Check specific angles 1. At \(x = \frac{\pi}{2}\): - \(\cos\left(\frac{\pi}{2}\right) = 0\) - \(\sin\left(\frac{\pi}{2}\right) = 1\) - Thus, \((\cos x)^5 + (\sin x)^3 = 0 + 1 = 1\) (valid solution). ### Step 7: Compile the solutions From our analysis, we found three solutions: - \(x = 0\) - \(x = \frac{\pi}{2}\) - \(x = 2\pi\) ### Conclusion The total number of real solutions in the interval \([0, 2\pi]\) is **3**.

To find the number of real solutions for the equation \((\cos x)^5 + (\sin x)^3 = 1\) in the interval \([0, 2\pi]\), we can follow these steps: ### Step 1: Analyze the equation The equation is given as: \[ (\cos x)^5 + (\sin x)^3 = 1 \] We know that both \((\cos x)^5\) and \((\sin x)^3\) are non-negative for values of \(x\) in the interval \([0, 2\pi]\). ...
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