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The general solution of (tan 5x-tan 4x)/...

The general solution of `(tan 5x-tan 4x)/(1+ tan 5 x tan 4x)=1` is

A

`n pi+pi/4, AA n in Z`

B

`n pi pm pi/4, AA n in Z`

C

`phi`

D

`n pi=pi/6, AA n in Z`

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The correct Answer is:
To solve the equation \(\frac{\tan 5x - \tan 4x}{1 + \tan 5x \tan 4x} = 1\), we can use the tangent subtraction formula. ### Step-by-Step Solution: 1. **Recognize the Identity**: The expression \(\frac{\tan A - \tan B}{1 + \tan A \tan B} = \tan(A - B)\). Here, let \(A = 5x\) and \(B = 4x\). Therefore, we can rewrite the equation as: \[ \tan(5x - 4x) = 1 \] 2. **Simplify the Left Side**: This simplifies to: \[ \tan(x) = 1 \] 3. **Find General Solutions**: The general solution for \(\tan(x) = 1\) is: \[ x = n\pi + \frac{\pi}{4} \quad \text{for } n \in \mathbb{Z} \] 4. **Substitute Back**: Since we want the solution in terms of \(x\), we can express it as: \[ x = n\pi + \frac{\pi}{4} \] 5. **Express in terms of \(x\)**: Since we are looking for the general solution of the original equation, we can write: \[ 5x - 4x = n\pi + \frac{\pi}{4} \] This gives: \[ x = n\pi + \frac{\pi}{4} \] ### Final Answer: Thus, the general solution of the equation is: \[ x = n\pi + \frac{\pi}{4}, \quad n \in \mathbb{Z} \]

To solve the equation \(\frac{\tan 5x - \tan 4x}{1 + \tan 5x \tan 4x} = 1\), we can use the tangent subtraction formula. ### Step-by-Step Solution: 1. **Recognize the Identity**: The expression \(\frac{\tan A - \tan B}{1 + \tan A \tan B} = \tan(A - B)\). Here, let \(A = 5x\) and \(B = 4x\). ...
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