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One of the general solutions of sqrt(3) ...

One of the general solutions of `sqrt(3) cos theta -3 sin theta =4 sin 2 theta cos 3 theta` is

A

`(3n pm 1) pi//12, AA n in Z`

B

`(4n pm 1) pi//9, AA n in Z`

C

`(3n pm 1) pi//9, AA n in Z`

D

`(3n pm 1) pi//3, AA n in Z`

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The correct Answer is:
To solve the equation \( \sqrt{3} \cos \theta - 3 \sin \theta = 4 \sin 2\theta \cos 3\theta \), we will follow these steps: ### Step 1: Rewrite the Right Side We start with the equation: \[ \sqrt{3} \cos \theta - 3 \sin \theta = 4 \sin 2\theta \cos 3\theta \] Using the double angle identity for sine, \( \sin 2\theta = 2 \sin \theta \cos \theta \), we can rewrite the right side: \[ 4 \sin 2\theta \cos 3\theta = 4(2 \sin \theta \cos \theta) \cos 3\theta = 8 \sin \theta \cos \theta \cos 3\theta \] ### Step 2: Rearrange the Equation Now, we can rearrange the equation: \[ \sqrt{3} \cos \theta - 3 \sin \theta - 8 \sin \theta \cos \theta \cos 3\theta = 0 \] ### Step 3: Factor Out Common Terms We can factor out \( \sin \theta \): \[ \sqrt{3} \cos \theta - \sin \theta (3 + 8 \cos \theta \cos 3\theta) = 0 \] ### Step 4: Set Each Factor to Zero This gives us two cases to consider: 1. \( \sqrt{3} \cos \theta = 0 \) 2. \( 3 + 8 \cos \theta \cos 3\theta = 0 \) ### Step 5: Solve the First Case For the first case: \[ \sqrt{3} \cos \theta = 0 \implies \cos \theta = 0 \] The general solution for \( \cos \theta = 0 \) is: \[ \theta = \frac{\pi}{2} + n\pi, \quad n \in \mathbb{Z} \] ### Step 6: Solve the Second Case For the second case: \[ 3 + 8 \cos \theta \cos 3\theta = 0 \implies 8 \cos \theta \cos 3\theta = -3 \] This can be rearranged to: \[ \cos \theta \cos 3\theta = -\frac{3}{8} \] ### Step 7: Use Trigonometric Identities Using the identity \( \cos A \cos B = \frac{1}{2} [\cos(A+B) + \cos(A-B)] \): \[ \cos \theta \cos 3\theta = \frac{1}{2} [\cos(4\theta) + \cos(2\theta)] = -\frac{3}{8} \] Multiplying through by 2: \[ \cos(4\theta) + \cos(2\theta) = -\frac{3}{4} \] ### Step 8: Solve the Equation This equation can be solved using numerical or graphical methods or further trigonometric identities. However, we can also find specific angles that satisfy this equation. ### Final General Solutions Combining the solutions from both cases, we have: 1. From \( \cos \theta = 0 \): \[ \theta = \frac{\pi}{2} + n\pi, \quad n \in \mathbb{Z} \] 2. From \( \cos \theta \cos 3\theta = -\frac{3}{8} \): This requires further analysis or numerical methods to find specific angles. ### Conclusion Thus, one of the general solutions of the given equation is: \[ \theta = \frac{\pi}{2} + n\pi, \quad n \in \mathbb{Z} \]

To solve the equation \( \sqrt{3} \cos \theta - 3 \sin \theta = 4 \sin 2\theta \cos 3\theta \), we will follow these steps: ### Step 1: Rewrite the Right Side We start with the equation: \[ \sqrt{3} \cos \theta - 3 \sin \theta = 4 \sin 2\theta \cos 3\theta \] Using the double angle identity for sine, \( \sin 2\theta = 2 \sin \theta \cos \theta \), we can rewrite the right side: ...
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