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If z=(a+i b)^5+(b+i a)^5 , then prove th...

If `z=(a+i b)^5+(b+i a)^5` , then prove that `R e(z)=I m(z),w h e r ea ,b in Rdot`

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To prove that \( \text{Re}(z) = \text{Im}(z) \) for \( z = (a + ib)^5 + (b + ia)^5 \), we will follow these steps: ### Step 1: Expand \( z \) We start with the expression for \( z \): \[ z = (a + ib)^5 + (b + ia)^5 \] ...
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