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If x and y are real numbers such that 16...

If x and y are real numbers such that `16^(x^(2)+y)+16^(x+y^2)=1`, then find the values of x and y.

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To solve the equation \( 16^{x^2 + y} + 16^{x + y^2} = 1 \) for real numbers \( x \) and \( y \), we can follow these steps: ### Step 1: Rewrite the Equation We start with the equation: \[ 16^{x^2 + y} + 16^{x + y^2} = 1 \] We can express \( 16 \) as \( 2^4 \): ...
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