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The solution of differential equation `(2y+x y^3)dx+(x+x^2y^2)dy=0` is (a) `( b ) (c) (d) x^(( e )2( f ))( g ) y+( h )(( i ) (j) x^(( k )3( l ))( m ) (n) y^(( o )3( p ))( q ))/( r )3( s ) (t)=c (u)` (v) (b) `( w ) (x) x (y) y^(( z )2( a a ))( b b )+( c c )(( d d ) (ee) x^(( f f )3( g g ))( h h ) (ii) y^(( j j )3( k k ))( l l ))/( m m )3( n n ) (oo)=c (pp)` (qq) (c) `( d ) (e) (f) x^(( g )2( h ))( i ) y+( j )(( k ) (l) x^(( m )4( n ))( o ) (p) y^(( q )4( r ))( s ))/( t )4( u ) (v)=c (w)` (x) (d) None of these

A

`x^(2)y+(x^(3)y^(3))/3=c`

B

`xy^(2)+(x^(3)y^(3))/3=c`

C

`x^(2)y+(x^(4)y^(4))/4=c`

D

None of these

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To solve the differential equation \( (2y + xy^3)dx + (x + x^2y^2)dy = 0 \), we will follow these steps: ### Step 1: Rewrite the Differential Equation We start with the given equation: \[ (2y + xy^3)dx + (x + x^2y^2)dy = 0 \] This can be rearranged to: \[ (2y + xy^3)dx = -(x + x^2y^2)dy \] ### Step 2: Separate Variables We can separate the variables by dividing both sides by \( (x + x^2y^2)(2y + xy^3) \): \[ \frac{dx}{x + x^2y^2} = -\frac{dy}{2y + xy^3} \] ### Step 3: Integrate Both Sides Now we will integrate both sides. We can integrate the left side with respect to \( x \) and the right side with respect to \( y \). #### Left Side Integration For the left side: \[ \int \frac{dx}{x + x^2y^2} \] This can be simplified by factoring out \( x \): \[ \int \frac{dx}{x(1 + xy^2)} = \int \left( \frac{1}{x} - \frac{y^2}{1 + xy^2} \right)dx \] #### Right Side Integration For the right side: \[ -\int \frac{dy}{2y + xy^3} \] This can be simplified similarly. ### Step 4: Solve the Integrals After integrating both sides, we will have: \[ \ln |x| - \ln |1 + xy^2| = -\frac{1}{2} \ln |2y + xy^3| + C \] ### Step 5: Combine and Simplify We can combine the logarithmic terms and exponentiate both sides to eliminate the logarithm: \[ \frac{x}{1 + xy^2} = K(2y + xy^3)^{-\frac{1}{2}} \] where \( K = e^C \) is a constant. ### Step 6: Rearranging the Equation Rearranging gives us an implicit solution: \[ x^2y + \frac{x^3y^3}{3} = C \] ### Final Solution Thus, the solution of the differential equation is: \[ x^2y + \frac{x^3y^3}{3} = C \]

To solve the differential equation \( (2y + xy^3)dx + (x + x^2y^2)dy = 0 \), we will follow these steps: ### Step 1: Rewrite the Differential Equation We start with the given equation: \[ (2y + xy^3)dx + (x + x^2y^2)dy = 0 \] This can be rearranged to: ...
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The solution of the differential equation {1+xsqrt((x^2+y^2))}dx+{sqrt((x^2+y^2))-1}ydy=0 is equal to (a) ( b ) (c) (d) x^(( e )2( f ))( g )+( h )(( i ) (j) y^(( k )2( l ))( m ))/( n )2( o ) (p)+( q )1/( r )3( s ) (t) (u) (v)(( w ) (x) (y) x^(( z )2( a a ))( b b )+( c c ) y^(( d d )2( e e ))( f f ) (gg))^(( h h ) (ii) (jj)3/( k k )2( l l ) (mm) (nn))( o o )=c (pp) (qq) (rr) ( s s ) (tt) x+( u u )(( v v ) (ww) y^(( x x )3( y y ))( z z ))/( a a a )3( b b b ) (ccc)+( d d d )1/( e e e )2( f f f ) (ggg) (hhh) (iii)(( j j j ) (kkk) (lll) x^(( m m m )2( n n n ))( o o o )+( p p p ) y^(( q q q )2( r r r ))( s s s ) (ttt))^(( u u u ) (vvv) (www)1/( x x x )2( y y y ) (zzz) (aaaa))( b b b b )=c (cccc) (dddd) (eeee) ( f f f f ) (gggg) x-( h h h h )(( i i i i ) (jjjj) y^(( k k k k )2( l l l l ))( m m m m ))/( n n n n )2( o o o o ) (pppp)+( q q q q )1/( r r r r )3( s s s s ) (tttt) (uuuu) (vvvv)(( w w w w ) (xxxx) (yyyy) x^(( z z z z )2( a a a a a ))( b b b b b )+( c c c c c ) y^(( d d d d d )2( e e e e e ))( f f f f f ) (ggggg))^(( h h h h h ) (iiiii) (jjjjj)3/( k k k k k )2( l l l l l ) (mmmmm) (nnnnn))( o o o o o )=c (ppppp) (qqqqq)

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Tangent to a curve intercepts the y-axis at a point Pdot A line perpendicular to this tangent through P passes through another point (1,0). The differential equation of the curve is (a) ( b ) (c) y (d)(( e ) dy)/( f )(( g ) dx)( h ) (i)-x (j) (k)(( l ) (m) (n)(( o ) dy)/( p )(( q ) dx)( r ) (s) (t))^(( u )2( v ))( w )=1( x ) (y) (b) ( z ) (aa) (bb)(( c c ) x (dd) d^(( e e )2( f f ))( g g ))/( h h )(( i i ) d (jj) x^(( k k )2( l l ))( m m ))( n n ) (oo)+( p p ) (qq)(( r r ) (ss) (tt)(( u u ) dy)/( v v )(( w w ) dx)( x x ) (yy) (zz))^(( a a a )2( b b b ))( c c c )=0( d d d ) (eee) (c) ( d ) (e) y (f)(( g ) dx)/( h )(( i ) dy)( j ) (k)+x=1( l ) (m) (d) None of these

CENGAGE ENGLISH-DIFFERENTIAL EQUATIONS-SINGLE CORRECT ANSWER TYPES
  1. The solution of the differential equation 2x ^(2)y (dy)/(dx) = tan ( x...

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  2. The solution of the differential equation {1/x-y^(2)/(x-y)^(2)}dx+{x^...

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  3. The solution of differential equation (2y+x y^3)dx+(x+x^2y^2)dy=0 is (...

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  4. The solution of y e^(-x/y)dx-(x e^((-x/y))+y^3)dy=0 is (a) ( b ) (c...

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  5. The curve satisfying the equation (dy)/(dx)=(y(x+y^3))/(x(y^3-x)) and ...

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  6. The solution of differential equation (x+y(dy)/(dx))/(y-x(dy)/(dx)) ...

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  7. The solution of the differential equation (dy)/(dx)=(3x^2y^4+2x y)/(x^...

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  8. The solution of the differential equation {1+xsqrt((x^2+y^2))}dx+{sqrt...

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  9. The solution of the differential equation y(2x^(4)+y)(dy)/(dx) = (1-...

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  10. The solution of the differential equation (xcoty + log cosx)dy +(logsi...

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  11. If dy/dx=(e^y-x)^(-1), where y(0)=0 , then y is expressed explicitly...

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  12. The general solution of the differential equation, y^(prime)+yvarph...

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  13. The integrating factor of the differential equation (dy)/(dx)(x(log)...

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  14. The solution of the differential equation x(x^2+1)((dy)/(dx))=y(1-x^2)...

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  15. Integrating factor of differential equation cosx(dy)/(dx)+ysinx=1 is (...

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  16. Solution of the equation cos^2x(dy)/(dx)-(tan2x)y=cos^4x, where |x|< ...

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  17. If integrating factor of x(1-x^2)dy+(2x^2y-y-a x^3)dx=0 is e^(intp dx...

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  18. A function y=f(x) satisfies (x+1)f^(prime)(x)-2(x^2+x)f(x)=(e^x^2)/((x...

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  19. The general solution of the equation (dy)/(dx)=1+x y is

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  20. The solution of the differential equation ((x+2y^3)dy)/(dx)=y is

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