Let f(x)=cospix+10x+3x^2+x^3,-2lt=xlt=3....

Let `f(x)=cospix+10x+3x^2+x^3,-2lt=xlt=3.` The absolute minimum value of `f(x)` is 0 (b) `-15` (c) `3-2pi` none of these

-15

`3 -2pi`

none of these

Text Solution

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The correct Answer is:

f(x) =`-pisin pi x +10+ 6x+3x^(2)`
`=3(x+1)^(2)+7 pi sin pi x gt 0 for all x `
Thus f(X) is increasing in `-2lexle3`
So absolute minimum =f -(2)=1 -20+12-8

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