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Consider `P(x)` to be a polynomial of degree 5 having extremum at `x=-1,1,` and `("lim")_(xvec0)((p(x))/(x^3)-2)=4` . Then the value of `[P(1)]` is (where [.] represents greatest integer function)___

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The correct Answer is:
2.4

Give `underset(xrarr0)lim p(x)/(x^(3))-2=4`
`therefore underset(xrarr0)lim(p(x))/(x^(3))=6`
consider P(x) =`ax^(5)+bx^(4)+6x^(3)`
Now `P(-1)=0 rarr5a-4b=-018`
and `P(1)=0 rarr 5a+4b=-18`
Hence P(x) =`(-18)/(5)x^(5)+6x^(3)`
or P(1)`=12/3`
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