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L e tf(x)={x+2,x<-1x^2,-1lt=x<1(x-2)^2,x...

`L e tf(x)={x+2,x<-1x^2,-1lt=x<1(x-2)^2,xgeq1` Then number of times `f^(prime)(x)` changes its sign in `(-oo,oo)` is___

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To determine the number of times \( f'(x) \) changes its sign in the interval \( (-\infty, \infty) \), we will follow these steps: ### Step 1: Define the function piecewise The function \( f(x) \) is given as: \[ f(x) = \begin{cases} x + 2 & \text{for } x < -1 \\ x^2 & \text{for } -1 \leq x < 1 \\ (x - 2)^2 & \text{for } x \geq 1 \end{cases} \] ### Step 2: Differentiate the function Now, we will differentiate \( f(x) \) in each piece of the piecewise function: - For \( x < -1 \): \[ f'(x) = 1 \] - For \( -1 \leq x < 1 \): \[ f'(x) = 2x \] - For \( x \geq 1 \): \[ f'(x) = 2(x - 2) = 2x - 4 \] ### Step 3: Identify critical points Next, we need to find the points where \( f'(x) = 0 \) or is undefined: - For \( f'(x) = 1 \) (for \( x < -1 \)), it does not change sign. - For \( f'(x) = 2x \) (for \( -1 \leq x < 1 \)): \[ 2x = 0 \implies x = 0 \] - For \( f'(x) = 2x - 4 \) (for \( x \geq 1 \)): \[ 2x - 4 = 0 \implies x = 2 \] ### Step 4: Analyze sign changes Now we will analyze the sign of \( f'(x) \) in the intervals determined by the critical points: 1. For \( x < -1 \): - \( f'(x) = 1 \) (positive) 2. For \( -1 \leq x < 0 \): - \( f'(x) = 2x \) (negative when \( x < 0 \)) 3. For \( 0 < x < 1 \): - \( f'(x) = 2x \) (positive) 4. For \( 1 \leq x < 2 \): - \( f'(x) = 2x - 4 \) (negative when \( x < 2 \)) 5. For \( x \geq 2 \): - \( f'(x) = 2x - 4 \) (positive) ### Step 5: Count the sign changes Now we summarize the sign changes: - From positive (1) to negative (at \( x = 0 \)) - **1 change** - From negative (at \( x = 0 \)) to positive (at \( x = 1 \)) - **1 change** - From positive (at \( x = 1 \)) to negative (at \( x = 2 \)) - **1 change** - From negative (at \( x = 2 \)) to positive (for \( x > 2 \)) - **1 change** ### Conclusion Thus, the total number of times \( f'(x) \) changes its sign in the interval \( (-\infty, \infty) \) is: \[ \text{Total changes} = 4 \] ### Final Answer The number of times \( f'(x) \) changes its sign in \( (-\infty, \infty) \) is **4**. ---

To determine the number of times \( f'(x) \) changes its sign in the interval \( (-\infty, \infty) \), we will follow these steps: ### Step 1: Define the function piecewise The function \( f(x) \) is given as: \[ f(x) = \begin{cases} x + 2 & \text{for } x < -1 \\ ...
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