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The number of nonzero integral values of...

The number of nonzero integral values of `a` for which the function `f(x)=x^4+a x^3+(3x^2)/2+1` is concave upward along the entire real line is___________

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To determine the number of nonzero integral values of \( a \) for which the function \[ f(x) = x^4 + ax^3 + \frac{3x^2}{2} + 1 \] is concave upward along the entire real line, we need to analyze the second derivative of the function. ### Step 1: Find the first derivative \( f'(x) \) The first derivative of \( f(x) \) is calculated as follows: \[ f'(x) = \frac{d}{dx}(x^4) + \frac{d}{dx}(ax^3) + \frac{d}{dx}\left(\frac{3x^2}{2}\right) + \frac{d}{dx}(1) \] Calculating each term gives: \[ f'(x) = 4x^3 + 3ax^2 + 3x \] ### Step 2: Find the second derivative \( f''(x) \) Now, we differentiate \( f'(x) \) to find \( f''(x) \): \[ f''(x) = \frac{d}{dx}(4x^3) + \frac{d}{dx}(3ax^2) + \frac{d}{dx}(3x) \] Calculating each term gives: \[ f''(x) = 12x^2 + 6ax + 3 \] ### Step 3: Set the condition for concavity For the function to be concave upward along the entire real line, we need: \[ f''(x) \geq 0 \quad \text{for all } x \] This means that the quadratic \( 12x^2 + 6ax + 3 \) must not have any real roots, which occurs when its discriminant is less than or equal to zero. ### Step 4: Calculate the discriminant The discriminant \( D \) of the quadratic \( Ax^2 + Bx + C \) is given by: \[ D = B^2 - 4AC \] For our quadratic \( 12x^2 + 6ax + 3 \): - \( A = 12 \) - \( B = 6a \) - \( C = 3 \) Thus, the discriminant is: \[ D = (6a)^2 - 4 \cdot 12 \cdot 3 \] Calculating this gives: \[ D = 36a^2 - 144 \] ### Step 5: Set the discriminant less than or equal to zero We need: \[ 36a^2 - 144 \leq 0 \] This simplifies to: \[ 36a^2 \leq 144 \] Dividing through by 36: \[ a^2 \leq 4 \] Taking the square root of both sides gives: \[ -2 \leq a \leq 2 \] ### Step 6: Identify nonzero integral values of \( a \) The integral values of \( a \) that satisfy this inequality are: \[ -2, -1, 1, 2 \] The nonzero integral values are: \[ -2, -1, 1, 2 \] ### Conclusion Thus, the number of nonzero integral values of \( a \) is: \[ \boxed{4} \]

To determine the number of nonzero integral values of \( a \) for which the function \[ f(x) = x^4 + ax^3 + \frac{3x^2}{2} + 1 \] is concave upward along the entire real line, we need to analyze the second derivative of the function. ...
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Concavity and convexity : if f''(x) gt 0 AA x in (a,b) then the curve y=f(x) is concave up ( or convex down) in (a,b) and if f''(x) lt 0 AA x in (a,b) then the curve y=f(x) is concave down (or convex up ) in (a,b) Inflection point : The point where concavity of the curve changes is known as point of inflection (at inflection point f''(x) is equal to 0 or undefined) Exhaustive set of values of 'a' for which the function f(x) =x^(4) +ax^(3)+(3x^(2))/(2)+1 will be concave upward along the entire real line is : (A) [-1,1] (B) [-2,2] (C) [0,2] (D) [0,4]

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CENGAGE ENGLISH-MONOTONICITY AND MAXIMA MINIMA OF FUNCTIONS-Numerical Value Type
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