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The temperature of a body falls from 40^...

The temperature of a body falls from `40^(@)C` to `36^(@)C` in 5 minutes when placed in a surrounding of constant temperature `16^(@)C` Find the time taken for the temperature of the body to become `32^(@)C`.

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To solve the problem, we will use Newton's Law of Cooling, which describes the rate of temperature change of an object in relation to the temperature of its surroundings. ### Step-by-Step Solution: 1. **Identify the Given Values**: - Initial temperature of the body (T1) = 40°C - Final temperature of the body after 5 minutes (T2) = 36°C - Surrounding temperature (T0) = 16°C ...
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