The radius of a gold nucleus (Z=79) is about `7.0*10^(-10) m`. Assume that the positive charge is distributed uniformly throughout the the nuclear volume. Find the strength of the electric field at (a) the surface of the nucleus and (b) at the middle point of a radius. Remembering that gold is a conductor, is it justified to assume that the positive charge is uniformly distributed over the entire volume of the nucleus and does not come to the outer surface?

Explanation

To solve the problem, we will calculate the electric field at the surface of the gold nucleus and at the midpoint of its radius using Gauss's Law.

### Given Data:
- Atomic number of gold (Z) = 79
- Charge of a proton (e) = \(1.6 \times 10^{-19} \, \text{C}\)
- Radius of the gold nucleus (R) = \(7.0 \times 10^{-10} \, \text{m}\)

### Step 1: Calculate the total charge of the gold nucleus
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