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The sum of the series 1/(2!)-1/(3!)+1/(4...

The sum of the series `1/(2!)-1/(3!)+1/(4!)-...` upto infinity is (1) `e^(-2)` (2) `e^(-1)` (3) `e^(-1//2)` (4) `e^(1//2)`

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To find the sum of the series \( S = \frac{1}{2!} - \frac{1}{3!} + \frac{1}{4!} - \frac{1}{5!} + \cdots \) up to infinity, we can use the Taylor series expansion of the exponential function \( e^x \). ### Step 1: Write the Taylor series for \( e^x \) The Taylor series expansion for \( e^x \) is given by: \[ e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!} ...
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