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How many milli-gram of iron (Fe^(2+)) a...

How many milli-gram of iron `(Fe^(2+))` are equal to 1mL of 0.1055N `K_(2) Cr_(2)O_7` equivalent ?

A

5.9 mg

B

0.59 mg

C

59 mg

D

`59 xx 10^(-3) mg`

Text Solution

Verified by Experts

The correct Answer is:
A
`w/56 xx100=1xx0.1055`
`w = (0.1055xx56)/1000 = 5.9` mg
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