The acceleration of the centre of mass of a uniform solid disc rolling down an inclined plane of angle `theta` is

Options

A. `(1)/(3) g sin theta`
B. `(2)/(3) g sin theta`
C. `g sin theta`
D. `(1)/(4) g sin theta`

Answer

B

Explanation

`because a = (g sin theta)/(1 + (k^2)/(R^2))`
where k is the radius of gyration and R is the radius of the body .
But for a solid uniform disc `(k^(2))/(R^(2)) = (1)/(2)`
`therefore a = (g sin theta)/(1 + (1)/(2)) = (2)/(3) g sin theta`