The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration ‘ a ’ is `3 : 2`. The value of ‘ a ’ is ( g - Acceleration due to gravity of the earth)

Options

A. `3/2 g`
B. `(g)/(3)`
C. `g`
D. `(2)/(3)g`

Answer

B

Explanation

`(3)/(2) = (mg) /(m(g-a)) or 3g - 3a = 2g or a =(g)/(3)`