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A string of length L and mass M is lying...

A string of length L and mass M is lying on a horizontal table. A force F is applied at one of its ends. Tension in the string at a distance x from the end at which force is applied is

A

Zero

B

F

C

`(F(L-y))/(L)`

D

`(F(l-y))/(M )`

Text Solution

Verified by Experts

The correct Answer is:
C
Acceleration of the rope ` a= (F )/(M)`

Now , considering the motion of the part AB of the rope [ which has mas `(M//L)y` and acceleration given by eq(I) ] assuming that tension at B is T
` F-T =((M)/(L ) y) xx a or F- T =(M )/(L ) y xx (F) /(M )=(Fy)/(L )`
` or t-F -F (y)/(L ) =F (1- (y)/(L ) ) = (F(L-y))/( L)`
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Knowledge Check

  • A uniform thick string of length 5 m is resting on a horizontal frictionless surface. It is pulled by a horizontal force of 5 N from one end. The tension in the string at 1m from the force applied is :

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