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Bullets of 0.03 kg mass each hit a plate...

Bullets of `0.03 kg` mass each hit a plate at the rate of `200` bullets per second with a velocity of `30 m//s`. The average force acting on the plate in newton is

A

120

B

180

C

300

D

480

Text Solution

Verified by Experts

The correct Answer is:
D
Change in momentum of one bullet
`=m (v- u) = 0.03 xx {50 - (-30 ) } = 2.4 kg ms^(-1)`
Average force = rate of change of momentum of 200 bullets
`= 200 xx 2.4 = 480 N`
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